Goal: How much traffic or budget gives you a good chance of a conversion?
Suppose your conversion rate is p (e.g. 5%), and you want to know:
How many independent clicks (n) do I need for at least a given probability (q) of at least one conversion?
Step 1: Probability of no conversions
Each visit (or click) has a chance p of converting. That means the chance of not converting in one visit is 1-p.
For n independent visits, the probability no one converts is:
(Probability of 0 conversions after n visits) = (1-p)^n
Step 2: Probability of at least one conversion
We want the probability of at least 1 conversion in n visits.
This is 1 minus the probability of no conversions:
Probability (at least 1 conversion) = 1 - (1-p)^n
Let’s call this probability q.
Step 3: Solve for n
You want the probability above to be at least q. Rearranging the formula:
1 - (1 - p)n = q
We solve for n:
-
Subtract 1 from both sides:
(1 - p)n = 1 - q -
Take the natural logarithm ln() of both sides:
ln((1-p)^n) = ln(1-q) -
Use log rules: ln(a^b) = b*ln(a)
n * ln(1-p) = ln(1-q) -
Solve for n:
n = ln(1-q) / ln(1-p)
- p = conversion rate (as a decimal, e.g. 0.05 for 5%)
- q = desired probability (as a decimal, e.g. 0.9 for 90%)
Example: For a 5% conversion rate and 90% desired probability:
n = ln(1-0.90) / ln(1-0.05) ≈ ln(0.1)/ln(0.95) ≈ -2.3026 / -0.05129 ≈ 44.9
So, you need at least 45 visits to have a 90% chance of at least one conversion!
← Back to Calculator
n = ln(1-0.90) / ln(1-0.05) ≈ ln(0.1)/ln(0.95) ≈ -2.3026 / -0.05129 ≈ 44.9
So, you need at least 45 visits to have a 90% chance of at least one conversion!